0=6x^2+9x-195

Solution for 0=6x^2+9x-195 equation:

0=6x^2+9x-195

We move all terms to the left:

0-(6x^2+9x-195)=0

We add all the numbers together, and all the variables

-(6x^2+9x-195)=0

We get rid of parentheses

-6x^2-9x+195=0

a = -6; b = -9; c = +195;
Δ = b2-4ac
Δ = -92-4·(-6)·195
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-69}{2*-6}=\frac{-60}{-12}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+69}{2*-6}=\frac{78}{-12}
=-6+1/2
$